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Vinogradovsky District

Administrative division of Arkhangelsk Oblast, Russia

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Vinogradovsky District (Russian: Виногра́довский райо́н) is an administrative district (raion), one of the twenty-one in Arkhangelsk Oblast, Russia. As a municipal division, it is incorporated as Vinogradovsky Municipal District.

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Texto em inglês Ainda não há artigo no teu idioma: trecho em inglês.

Vinogradovsky District (Russian: Виногра́довский райо́н) is an administrative district (raion), one of the twenty-one in Arkhangelsk Oblast, Russia. As a municipal division, it is incorporated as Vinogradovsky Municipal District. It is located in the center of the oblast and borders with Pinezhsky District in the northeast, Verkhnetoyemsky District in the southeast, Shenkursky District in the south, Plesetsky District in the southwest, the town of oblast significance of Mirny in the west, and with Kholmogorsky District in the northwest. The area of the district is 12,600 square kilometers (4,900 sq mi). Its administrative center is the urban locality (an urban-type settlement) of Bereznik. Population: 16,753 (2010 census); 20,862 (2002 census); 24,834 (1989 Soviet census). The population of Bereznik accounts for 35.9% of the district's total population. The district is named after Pavlin Vinogradov, a Bolshevik and an active participant of the October Revolution and the Russian Civil War. In 1918, Vinogradov was sent to Arkhangelsk and eventually charged with the organization of the Bolshevik resistance to British and American troops. Vinogradov died in combat at the village of Shidrovo, now within the area of the district.

Texto: Wikipédia em inglês, CC BY-SA 4.0. · Imagem: GENVELES (CC BY-SA 3.0) ·

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