Ceva's theorem

Theorem in planar Euclidean geometry

Nº Q213603 ★★

Uncommon · Knowledge

Ceva's theorem

Theorem in planar Euclidean geometry

In Euclidean geometry, Ceva's theorem is a theorem about triangles. Given a triangle △ABC, let the lines AO, BO, CO be drawn from the vertices to a common point O (not on one of the sides of △ABC), to meet opposite sides at D, E, F respectively. (The segments AD, BE, CF are known as cevians.)

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From Wikipedia

In Euclidean geometry, Ceva's theorem is a theorem about triangles. Given a triangle △ABC, let the lines AO, BO, CO be drawn from the vertices to a common point O (not on one of the sides of △ABC), to meet opposite sides at D, E, F respectively. (The segments AD, BE, CF are known as cevians.) Then, using signed lengths of segments, A F ¯ F B ¯ ⋅ B D ¯ D C ¯ ⋅ C E ¯ E A ¯ = 1. {\displaystyle {\frac {\overline {AF}}{\overline {FB}}}\cdot {\frac {\overline {BD}}{\overline {DC}}}\cdot {\frac {\overline {CE}}{\overline {EA}}}=1.} In other words, the length XY is taken to be positive or negative according to whether X is to the left or right of Y in some fixed orientation of the line. For example, AF / FB is defined as having positive value when F is between A and B and negative otherwise. Ceva's theorem is a theorem of affine geometry, in the sense that it may be stated and proved without using the concepts of angles, areas, and lengths (except for the ratio of the lengths of two line segments that are collinear). It is therefore true for triangles in any affine plane over any field. A slightly adapted converse is also true: If points D, E, F are chosen on BC, AC, AB respectively so that A F ¯ F B ¯ ⋅ B D ¯ D C ¯ ⋅ C E ¯ E A ¯ = 1 , {\displaystyle {\frac {\overline {AF}}{\overline {FB}}}\cdot {\frac {\overline {BD}}{\overline {DC}}}\cdot {\frac {\overline {CE}}{\overline {EA}}}=1,} then AD, BE, CF are concurrent, or all three parallel. The converse is often included as part of the theorem. The theorem is often attributed to Giovanni Ceva, who published it in his 1678 work De lineis rectis. But...

Text: Wikipédia, CC BY-SA 4.0. · Image: 4C (CC BY-SA 3.0) ·

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